When carbon disulfide gas and oxygen gas react to form sulfur dioxide gas and carbon dioxide gas, 4 moles of oxygen are required to produce 2 moles of sulfur dioxide gas. If 3.0 m^3 of oxygen is consumed, this reaction will produce 6.0 moles of sulfur dioxide gas, which would be a volume of 15.6 m^3 of sulfur dioxide gas.

## Reactants

The reactants for this reaction are carbon disulfide gas and oxygen gas. Carbon disulfide gas is a colorless, flammable gas with a pungent odor. It has the chemical formula CS2 and is made up of one carbon atom and two sulfur atoms. Oxygen gas is a colorless, odorless gas that is made up of two oxygen atoms. It is the most abundant element in the Earth’s atmosphere and has the chemical formula O2.

## Products

The products of this reaction are sulfur dioxide gas and carbon dioxide gas. Sulfur dioxide gas is a colorless, nonflammable gas with a pungent odor. It has the chemical formula SO2 and is made up of one sulfur atom and two oxygen atoms. Carbon dioxide gas is a colorless, odorless gas that is made up of one carbon atom and two oxygen atoms. It has the chemical formula CO2.

## Calculation

The amount of sulfur dioxide gas that will be produced by this reaction can be calculated by using the stoichiometry of the reaction. The stoichiometry of the reaction states that 4 moles of oxygen are required to produce 2 moles of sulfur dioxide gas. Therefore, if 3.0 m^3 of oxygen are consumed, this will produce 6.0 moles of sulfur dioxide gas. The volume of sulfur dioxide gas that would be produced by this reaction can then be calculated by using the ideal gas law, which states that the volume of a gas is equal to the number of moles of the gas multiplied by the molar volume (a constant equal to 24.5 L/mol at standard temperature and pressure). This calculation shows that the reaction of 3.0 m^3 of oxygen with carbon disulfide gas will produce a volume of 15.6 m^3 of sulfur dioxide gas.

## Related Questions

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