## Calculating the Amount of Manganese Dioxide Needed to Produce 355mL of Chlorine Gas

The reaction of manganese dioxide and hydrochloric acid, known as the Chlorine Gas Law, can be used to calculate the amount of manganese dioxide needed to produce a certain volume of chlorine gas. In order to produce 355 mL of chlorine gas at 25 degrees Celsius and 785 Torr, the following equation must be used:

MnO2(s) + 4HCl(aq) → MnCl2(aq) + 2H2O(l) + Cl2(g).

## Calculation of the Amount of MnO2 Needed

In order to calculate the amount of manganese dioxide needed to produce 355 mL of chlorine gas, the Ideal Gas Law must be used. The Ideal Gas Law states that the volume of a gas is equal to the number of moles of the gas multiplied by the ideal gas constant, R, divided by the pressure of the gas. The equation is as follows:

V = nR/P

In this case, V is equal to 355 mL, n is equal to the moles of chlorine gas produced, R is equal to 0.0821 L atm/molK and P is equal to 785 Torr. Therefore, the equation becomes:

355 mL = n(0.0821 L atm/molK)/785 Torr

By solving for n, the moles of chlorine gas produced can be determined.

n = 355 mL / (0.0821 L atm/molK / 785 Torr) = 0.0045 mol

## Calculation of the Amount of MnO2 Needed to Produce 0.0045 mol of Cl2

Now that the moles of chlorine gas produced are known, the amount of manganese dioxide needed to produce 0.0045 mol of chlorine gas can be determined. The equation for the reaction of manganese dioxide and hydrochloric acid is as follows:

MnO2(s) + 4HCl(aq) → MnCl2(aq) + 2H2O(l) + Cl2(g).

To produce 0.0045 mol of chlorine gas, 4 times the amount of moles of hydrochloric acid, or 0.018 mol HCl, must be used. The equation becomes:

MnO2(s) + 0.018 mol HCl(aq) → MnCl2(aq) + 2H2O(l) + 0.0045 mol Cl2(g).

The equation can be solved for MnO2(s) by dividing both sides of the equation by 0.018 mol HCl(aq).

MnO2(s) = 0.0045 mol Cl2(g) / 0.018 mol HCl(aq)

Therefore, the amount of manganese dioxide needed in order to produce 355 mL of chlorine gas at 25 degrees Celsius and 785 Torr is 0.0045 mol Cl2(g) / 0.018 mol HCl(aq) = 0.25 mol MnO2(s).

## Related Questions

• What is the equation for the reaction of manganese dioxide and hydrochloric acid?
• What is the Ideal Gas Law?
• How many moles of hydrochloric acid are needed to produce 0.0045 mol of chlorine gas?
• What is the equation for the Ideal Gas Law?
• What is the volume of chlorine gas produced when 0.018 mol of hydrochloric acid is used?
• What is the pressure of chlorine gas produced when 0.018 mol of hydrochloric acid is used?
• How many moles of chlorine gas are produced when 0.25 mol of manganese dioxide is used?
• What is the temperature of chlorine gas produced when 0.018 mol of hydrochloric acid is used?
• What is the molar mass of manganese dioxide?
• What is the molar mass of hydrochloric acid?