2y+9x+1 as a Sum of Three Terms

The equation 2y+9x+1 can be written as a sum of three terms, which are y+2x+1, y+7x, and 0. This can be shown by breaking the equation into the three components and then reorganizing them so that each is written as a sum of two terms.

Breaking the Equation into Components

The equation 2y+9x+1 can be broken down into its components by using the distributive property. This property states that when multiplying a monomial by a polynomial, each term of the polynomial should be multiplied by the monomial. In this case, the monomial is 2y and the polynomial is 9x+1. Applying the distributive property, the equation can be broken down into the components 2y+2x+2y+7x+1.

Reorganizing the Components

After the equation has been broken down into its components, it can then be rearranged into three terms. The first term is 2y+2x+1, the second is 2y+7x, and the third is 0. This can be done by combining the two terms with the same variable, y. This results in y+2x+1 and y+7x being two of the terms. The third term, 0, can be obtained by subtracting the sum of the other two terms from the original equation. This results in the equation 2y+9x+1 being written as a sum of three terms.

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